Home
Class 11
PHYSICS
A particle executing simple harmonic mot...

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is…………….

A

3Hz

B

2 Hz

C

4Hz

D

1 Hz

Text Solution

Verified by Experts

The correct Answer is:
D
`A=5 cm = 5 xx 10^(-2) m , upsilon = (max ) = 31.4 cm//s = 31.4 xx 10^(-2) m//s`
maximum speed `V_(max) = 2 pi eta xx A `
` therefore n = (V_(max))/( 2pi A ) = ( 31.4 xx 10^(-2) )/( 2 pi xx 5xx 10^(-2)) =( 31.4 )/( 10 xx3.14 ) = n=1 Hz`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER -3 (SOLVED)

    FULL MARKS|Exercise PART-II|9 Videos

  • SAMPLE PAPER -3 (SOLVED)

    FULL MARKS|Exercise PART-III|9 Videos

  • SAMPLE PAPER -10 (SOLVED)

    FULL MARKS|Exercise PART-IV|12 Videos

  • SAMPLE PAPER -4

    FULL MARKS|Exercise PART-IV|10 Videos

Similar Questions

Explore conceptually related problems

The maximum velocity of a particle , executing simple harmonic motion with an amplitude 7mm" is "4.4ms^(-1) . The period of oscillation is

A particle executes simple harmonic motion with a frequency. (f). The frequency with which its kinetic energy oscillates is.

A particle executes a simple harmonic motion of amplitude 1.0 cm along the principal axis of a convex lens of focal length 12 cm. The mean position of oscillation is at 20 cm from the lens. Find the amplitude of oscillation of the image of the particle.

For a particle executing simple harmonic motion, the acceleration is proportional to

The resultant force acting on a particle executing simple harmonic motion is 4N when it is 5cm away from the centre of oscillation. Find the spring constant.

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then find its time period in seconds.

A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6s. At t=0 it is at position x=5 cm going towards positive x-direction. Write the equation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t=4s.

A block of mass 0.5 kg hanging from a vertical spring executes simple harmonic motion of amplitude 0.1 m and time period 0.314s. Find the maximum fore exerted by the spring on the blockl.

A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.