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A solid cylinder of mass 20kg rotates ab...

A solid cylinder of mass 20kg rotates about it axis with anguler speed `100s^(-1)` the radius of the cylinder is 0.25m, Calculate moment of intertia of the solid cylinder.

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Given Data : R=0.25m,M=20KG, `omega=100s^(-1)`
moment of inertia of the solid cylinder=`(MR^(2))/(2)`
`=(20xx(0.25)^(2))/(2)=0.625kgm^(2)`
`therefore` K.E of rotation` =(1)/(2)Iomega^(2)`
`(1)/(2)xx0.625xx(100^(2))=3125J`
`therefore` Anguler momentum `L=Iomega=0.625xx100`
`L=62.5Js`
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