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A wire 10 m long has a cross-sectional a...

A wire 10 m long has a cross-sectional area `1.25 xx 10^(-4) m^(2)`. It is subjected to a load of 5 kg. If Young's modulus of the material is `4 xx 10^(10) N m^(-2)`, calculate the elongation produced in the wire. Take `g = 10 ms^(-2)`

Text Solution

Verified by Experts

We know that `(F)/(A)=Yxx(DeltaL)/(L)`
`DeltaL=(F/A)(L/Y)=((50)/(1.25xx10^(-4)))((10)/(4xx10^(10)))=10^(-4)m`
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