The wavelength of two sine waves are `lambda_(1) = 1 m` and `lambda_(2) = `6 m . Calculate the corresponding wave numbers .

Options

A. `1.05 rad m^(-1) and 6.28 rad m^(-1)`
B. `6.28 rad m^(-1) and 1.05 rad m6(-1)`
C. `1 rad m ^(-1) and 0.1666 rad m^(-1)`
D. `0.166 rad m^(-1) and rad m^(-1)`

Answer

B

Explanation

Standard wave equation, ` Y=A sin ( kx - omega t)`
` K_1 = ( 2pi )/( lamda_1) = ( 2pi )/( 1) = 6.28 rad m^(-1)`
` K_2 =(2pi )/( lamda_2) =(2pi )/( 6 ) =1.05 rad m^(-1)`