Home
Class 11
PHYSICS
A particle of mass 2 kg experiences two ...

A particle of mass 2 kg experiences two forces `verF = 5 hati + 8 hatj + 7 hatk and vecF _2 = 3 hati - 4hatj + 3hatk ` What is the acceleration of the particle?

Text Solution

Verified by Experts

We use Newton.s second law, `vecF_(n e t) = m veca `where `vecF = vecF_(1) + vecF _2 ` From the equations the acceleration is `veca = ( vecF _(n e t))/(m)`, where
` vecF _(n et) = ( 5+ 3 ) hati +(8 - 4) hatj (7+3) hatk`
` vecF_(n e t) = 8 hati + 4 hatj + 10 hatk `
` veca = ((8 ) /(2) ) hati +((4)/(2)) hatj +((10)/( 2)) hatk `
` vec a = 4 hati + 2hatj + 5 hatk `
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER-5 (SOLVED)

    FULL MARKS|Exercise PART-III|9 Videos
  • SAMPLE PAPER-5 (SOLVED)

    FULL MARKS|Exercise PART-IV|10 Videos
  • SAMPLE PAPER-5 (SOLVED)

    FULL MARKS|Exercise PART-IV|10 Videos
  • SAMPLE PAPER-14 (UNSOLVED)

    FULL MARKS|Exercise Part-IV|10 Videos
  • SOLVED PAPER -16 (UNSOLVED)

    FULL MARKS|Exercise PART-IV|5 Videos

Similar Questions

Explore conceptually related problems

A particle of mass 2 kg experiences two forces, vecP_1 = O , vecP_2 = O " and " vecF_2 = 3 hati - 4hatj + 3hatk . What is the acceleration of the particle?

The position vector of the particle is vecr=3t^2 hati+5t hatj+9hatk . What is the acceleration of the particle?

Given veca = 2hati + hatj - 8 hatk and vecb = hati + 3hatj - 4hatk then |veca + vecb| = ……………………… .

Find the scalar and vector products of two vectors. a = (3hati – 4hatj + 5hatk) and b = (– 2hati + hatj – 3hatk )