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If 5 L of water at 50^(@)C is mixed with...

If 5 L of water at `50^(@)C` is mixed with 4L of water at `30^(@)C`, what will be the final temperature of water? Take the specific heat capacity of water as `4184 J kg^(-1) K^(-1)`

Text Solution

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We can use the equation `T_f = (m_1 S_1 T_1 +m_2s_2 T_2)/( m_1s_1 +m_2 s_2 ) `
`m_1 5L = 5 kg and m_2 = 4L = 4 kg s_1 =s_2 and T_1 = 50 ^@ C = 323 K and T_2 = 30^@ C = 303 K`
so ` T_f =(m_1 T_1 +m_2 T_2)/( m_1 +m_2) = ( 5 x 323 +4 xx 303 )/( 5+4 ) = 314 .11 K`
` T_f = 314 .11 K - 273 K ~~ 41 ^@ C,`
suppose if we mix equal amount of water ` ( m_1 = m_2 )` with `50 ^@ C ` and `30^@C ,` then the final temperature is average of two temperatures .
Suppose if both the water are at `30^@C` then the final temperature will also `30^@C` . It implies that they are at equilibrium and no heat exchange takes place between each other.
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