Home
Class 11
PHYSICS
Explain how overtones are produced in a:...

Explain how overtones are produced in a: (a) Closed organ pipe (b) Open organ pipe

Text Solution

Verified by Experts

Closed organ pipes Look at the picture of a clarin e t , shown in firgure . It is a pipe with one closed and the other end open . If one end of a pipe is closed , the wave reflected at this closed end is `180^@ ` out of phase with the incoming wave . thus there is no displacement of the particles at the closed end . THerefore , nodes are formed at the closed end and antinodes are formed at open end .

(a) No motion of particles which leads to nodes at closed end and antinodes at open and ( fundamental mode ) ( N- node , A - antinode )
Let us consider the simplest mode of vibration of the air column called the fundamental mode . Anti - node is formed at the open and and node at closed end . from the figure .Let L be the length of the tube and the wavelength of the wave produced . for the fundamental mode of vibration ,we have
` L = ( lamda_1 )/( 4 ) or lamda_1 = 4L`
The frequency of the note emitted is
`f_1 = ( v)/( lamda_1) = ( v)/( 4 L)`
which is called the fundamental note :
Teh freqencies higher fundamental frequency can be produced by blowing air strongly at open end . Such frequencies are called overtones .
THe figure (b) shows the second mode of vibration having two nodes and two antinodes ,

` 4L = 3 lamda _2`
`L=(3lamda _2)/(4 ) or lamda _2 = ( 4L )/(3) `
The frequency for this ,
` f_2 =( V) /( lamda _2 ) = ( 3v )/( 4 L) = 3 F_1`
is called first over , since here , the frequency is three times the fundamental frequency it is called third harmonic .
The figure (c ) shows third mode of vibration having three nodes and three anti - nodes

We have ` 4L = 5 lamda_3`
` L= (5lamda_3) /( 4 ) or lamda_3 = ( 4 L )/( 5 )`
THe frequency `f_3 = ( V)/( lamda _3 ) = ( 5v )/( 4 L) = 5 F_1`
is called second over tone and since n=5 here , this is called fifth harmonic , hence the closed orgran pipe has only odd harmonics and frequency of the nth harmonic is ` f_n = ( 2 n +1) f_1` : Therefore the frequencies of harmonic are in the ratio
` F_1 : f_2 : F_3 : F_4 :... = 1:3:5:7:.............(3)`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER-5 (SOLVED)

    FULL MARKS|Exercise PART-III|9 Videos
  • SAMPLE PAPER-14 (UNSOLVED)

    FULL MARKS|Exercise Part-IV|10 Videos
  • SOLVED PAPER -16 (UNSOLVED)

    FULL MARKS|Exercise PART-IV|5 Videos

Similar Questions

Explore conceptually related problems

Germinal variation are produced in ____ of an organism.

The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If the length of the open pipe is 60 cm, what is the length closed pipe?

Find the fundamental, first overtone and second overtone frequencies of an open organ pipe of length 20 cm. Speed of sound in air is 340 m s^-1 .

The first overtone frequency of a closed organ pipe P_1 is equal to the fundamental frequency of an open organ pipe P_2 . If the length of the pipe P_1 is 30 cm, what will be the length of P_2 ?

Explain the excretory role of other organs.

Consider two organ pipes of same length in which are organ is closed and another organ pipe is open. If the fundamental frequency of closed pipe is 250 Hz. Calculate the fundamental frquency of the open pipe.

Assertion: The frequencies of harmonics are in the ratio 1:3:5:7, in the case of open organ pipe. Reason: The second harmonic for an open organ pipe is 2f_(1) .