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Work done by 0.1 mole of a gas at 27°C t...

Work done by 0.1 mole of a gas at 27°C to double its volume at constant pressure is
(R = 2 cal/mol/K)

A

54 cal

B

60 cal

C

546 cal

D

600 cal

Text Solution

Verified by Experts

The correct Answer is:
B
Workdone(W) = p.dv=nRT
`=0.1 xx (0.2 "cal") xx (273+27)=0.1 xx 2 xx 300`
W=60 cal
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