Calculate the value of g in the following two cases:
(a) If a mango of mass `1/2` kg falls from a tree from a height of 15 metres, what is the acceleration due to gravity when it beigns to fall?
(b) Consider a satellite orbiting the Earth in a circular orbit of radius 1600 km above the surface of the Earth. What is the acceleration experienced by the satellite due to Earth's gravitational force?

Explanation

`g^(.)=g(1-(2h)/(Re))`
`=g(1-(2 xx 1600 xx 10^(3))/(6400 xx 10^(3)))=g(1-(2)/(4))`
`g^(.)=g(1-(1)/(2))=(g)/(2)`
`g^(.)=(8)/(2)` (or) `g^(.)=(9.8)/(2)=4.9 ms^(-2)`