Calculate how many times more intense is 90 dB sound compared to 40 dB sound?

Explanation

Given Data: `L=log(I)/(I_(0))=logI-logI_(0)`
We get `90 dB = 9B=logI_(1)-logI_(0)` ...(1)
`40dB=4B=logI_(2)-logI_(0)` ...(2)
Subtract (2) from (1)
`-50dB=5B=logI_(1)-logI_(2)`
`5=log_(10)((I_(1))/(I_(2)))`
`(I_(1))/(I_(2))=10^(5)`