If the linear momentum of the object is inceaseby by 0.01% the the kinetic energy is increased by

Options

A. 0.0001
B. 0.0002
C. 0.0004
D. 0.0001

Answer

C

Explanation

The relation b/w linear momentum and kinetic energy
`P = sqrt(2mE_K) rArr E_K = (P^2)/(2m)`
If L is increased by 0.1 % `= P + (0.1)/(100) P`
`E_K = ( (P+(0.1)/(100) P)^2)/(2m) = (1.002001P^2)/(2m) = 1.002001E_K`
Increase in kinetic energy ` = (E_K - E_K)/(E_K) xx 100 = [ (1.002001E_K - E_K)/(E_K) ] xx 100 = 0.2%`