Home
Class 11
PHYSICS
The distance of planet Jupiter from the ...

The distance of planet Jupiter from the sun is 5.2 times that of the earth. Find the period of resolution of Jupiter around the sun.

Text Solution

Verified by Experts

Here ` r_1 = 5.2 r_e : T_3 = ? : T_e = 1 ` year
` therefore (T_3^2)/(T_c^2) = (r_3^3)/(r_e^3)`
` T_3 = T_e (r_3/r_e)^(3/2) = 1 xx ( (5.2 r_e)/(r_e) )^(3/2) ` = 11.86 years
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER - 9

    FULL MARKS|Exercise PART-III|9 Videos
  • SAMPLE PAPER - 8 (SOLVED)

    FULL MARKS|Exercise (PART - IV)|10 Videos
  • SAMPLE PAPER -1

    FULL MARKS|Exercise PART-IV|10 Videos

Similar Questions

Explore conceptually related problems

The period of a planet around Sun is 27 times that of Earth. The ratio of radius if planet's orbit to the radius of Earth's orbit is:

The diameter of the sun is 1.4 X 10^9m and its distance from the earth is 1.5 X 10^11 m . Find the radius of the image of the sun formed by a lens of focal length 20 cm.

The radius of orbit of a planet is two times that of Earth. The time period of planet is ........... years.

The distance of two planets from the Sun are 10^(13)and10^(12) metres respectively. The ratio of time periods of these two planets is:

The distance of two planets from the Sun are 10^(13)and10^(12) metres respectively. The ratio of time periods of these two planets is:

The time taken by Mars to revolve round the sun is 1.88 years. Find the ratio of average distance between mars and the sun to that between the earth and the sun.

The mass and diameter of a planet are twice those of the earth. What will be the time period of that pendulum on this planet which is a seconds pendulum on the earth.