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The displacement of a particle moving al...

The displacement of a particle moving along x-axis with respect to times is given by `x=at+bt^(2)-ct^(3)`. The dimensions of b are

A

`L^(0)T^(-3)`

B

LT

C

`LT^(-2)`

D

`LT^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
C
According to principle of homogeneity the displacement is `x = at+bt^2 -ct^3`
The dimensionally . `[L] = [LT^(-1)] + [T] + [ LT^(-2)] - [LT^(-3)] [T^3]`
`therefore ` the dimension of .b. is `LT^(-2)`
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