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A force of vecF = (4hati-3hatj+5hatk)N i...

A force of `vecF = (4hati-3hatj+5hatk)N` is applied at a point whose position vector is `vec r = (7hati+4hatj-2hatk)m`. Find the torque of force about the origin.

Text Solution

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`vecF= (4hati - 3hatj + 5hatk ) N`
`vecr = (7hati + 7hatj - 2hatk) m`
Torque `vectau = vecr xx vecF`
`= |{:(hati , hatj , hatk),(7,7,-2),(4,-3,5):}|`
`= (35-6)hati -(-8-35)hatj + (-21-28)hatk`
`=29hati + 43hatj-49hatk`
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