Home
Class 11
PHYSICS
A fly wheel rotates with a uniform angul...

A fly wheel rotates with a uniform angular acceleration. If its angular velocity increases form `20 pi` rad/s to `40 pi` rad/s in 10 seconds. Find the number of rotations in that period.

Text Solution

Verified by Experts

Initial angular velocity `omega_0` = `20 pi ` rad/sec
Final angular velocity `omega`= `40pi` rad/sec
Time (t) = 10 seconds
Angular acceleration `alpha = (omega-omega_0)/(t) =( 40 pi - 20 pi)/(10)`
`alpha = 2pi` rad/`sec^2`
Promotional Banner

Topper's Solved these Questions

  • SOLVED PAPER 12 (UNSOLVED)

    FULL MARKS|Exercise Part-III|9 Videos
  • SOLVED PAPER 12 (UNSOLVED)

    FULL MARKS|Exercise Part - IV|10 Videos
  • SOLVED PAPER 12 (UNSOLVED)

    FULL MARKS|Exercise Part - IV|10 Videos
  • SOLVED PAPER -16 (UNSOLVED)

    FULL MARKS|Exercise PART-IV|5 Videos
  • SOLVED PAPER 17 (UNSOLVED)

    FULL MARKS|Exercise Part-IV|10 Videos

Similar Questions

Explore conceptually related problems

A wheel is making revolutions about its axis with uniform angular acceleration. Starting from rest, till it reaches 100 rev/sec in 4 seconds. Find the angular acceleration.

A wheel rotating wilth unifrom angular acceleration covers 50 revolutions in the first five seconds after the start. Find the angular acceleration and the angular velocity at the end of five seconds.

A wheel is rotating with angular velocity 2 rad/s. It is subjected to a uniform angular acceleration 2 rad/s2 then the angular velocity after 10s is

Calculate the angular velocity in rad/sec. of a fly wheel making 300 rpm .

A wheel rotates with a constant acceleration of 2.0(rad)/s^2 . If the wheel starts from rest, how many revolutions will it make in the first 10 seconds?

A rod of length l rotates with a uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the rod is