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If the error in the measurement of radiu...

If the error in the measurement of radius is 2%, then the error in the determination of volume of the pshere will be

A

0.08

B

0.02

C

0.04

D

0.06

Text Solution

Verified by Experts

The correct Answer is:
D
Volume of the sphere, `V= 4/3 pi r^3`
% Error in the volume of the sphere, `(DeltaV)/(V) xx 100 = 3 xx ((Deltar)/(r) xx 100 ) = 3 xx 2%`
`(DeltaV)/(V) xx 100 = 6%`
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