Consider two springs with force constants `1 Nm^(-1)` and `2Nm^(-1)` connected in parallel. Calculate the effective spring constant `(k_(p))` and comment on `k_(p)`.

Explanation

`k_1 = 1 Nm^(-1) , k_2 =2 Nm^(-1)`
`k_p = k_1 + k_2 Nm^(-1)`
`k_p = 1+2 =3 Nm^(-1)`
`k_p gt k_1 and k_p gt k_2`
Therefore, the effective spring constant is greater than both `k_1 and k_2`.