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The temperature at which the K.E. of a g...

The temperature at which the K.E. of a gas molecules is double its value at `27^(@)C` is

Text Solution

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Average kinetic energy `prop` Temperature
`E prop T`
Hence if KE is double, then temperature has to be double,
`T = 2 xx (273 + 27)`
`T = 600 K`
`therefore T = (600- 273)^(@)C`
`T = 327^(@)`C
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