A particle executing a SHM has maximum acceleration at a distance of 0.5 cm from its mean position is `2cm//s^(2)` . What will be its velocity when it is at a distance of 1 cm from its mean position.

A particle executing SHM has an acceleration of 64cm//s^(2) with its displacement is 4 cm. Its time period, in seconds is……………

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then find its time period in seconds.

A particle is executing SHM along a straight line. Its velocities at dsitances x_1 and x_2 from the mean position are V_1 and V_2 , respectively. Its time period is

A particular executes SHM with a time period of 16s. At time t=2s , the particle crosses the mean position while at t= 4 , its velocity is 4ms^(-1) Find its a amplitude of motion.

A particle executing linear SHM has a maximum velocity of 40 cm s^(-1) and a maximum acceleration of 50 cm s^(-2) . Find is amplitude and the period of oscillaton. Maximum velocity,

A convex mirror has its radius of curvature 20 cm. Find the position of the image of an object placed at a distance of 12 cm from the mirror.

The acceleration of a particle performing S.H.M. is 12 cm/ s^(2) at a distance of 3 cm from the mean position. Its time period is _____ .

A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?

The maximum displacement of a particle executing SHM is 1 cm and the maximum acceleration is (1.57)^(2)cm//s^(2) . Its time period is……………..