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A rigid body rotates with an angular mom...

A rigid body rotates with an angular momentum L. If its kinetic energy is halved, the angular momentum becomes,

A

L

B

`(L)/(2)`

C

2L

D

`(L)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
Angular momentum, `L= sqrt(2mE_(K))`
If `E_(K)` is halved `E_(K).= (E_(K))/(2)`
New angular momentum, `L.= sqrt(2mE._(K))= sqrt((2mE_(K))/(2))`
`L.= (L)/(2)`
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