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A particle executing SHM, covers a displ...

A particle executing SHM, covers a displacement of half of amplitude in one second. Calculate its time period.

Text Solution

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Displacement, `X = A sin(omegat)`
`X= (A)/(2)`
`(A)/(2)= A sin(omegat)`
`(1)/(2)= sin(omegat) , omegat= (pi)/(6)`
`((2pi)/(T))t= (pi)/(6), t= (T)/(12)"sec"`
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