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The amplitude and time period of a simpl...

The amplitude and time period of a simple pendulum bob are `0.05m` and `2` s respectively. Then the maximum velocity of the bob is :

A

`0.157 ms^(-1)`

B

`0.257 ms^(-1)`

C

`0.10 ms^(-1)`

D

`0.025 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_(rms) = a omega = a ((2pi)/(T))`
` = 0.05 ((2pi)/(2) ) = 0.05 xx 3.14 `
` V_(rms) = 0.157 ms^(-1)`
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