Write down the equation of a freely falling body under gravity.

Explanation

(i) Distanced traveled by an object falling for time .t., u = 0 , s = d , a = g
`s = ut + 1/2 at^2`
` therefore = 1/2 "gt"^2`
Time .t. taken for an object to fail distance .d..
` t = sqrt((2d)/(g))`
Instantaneous velocity `v_i` of a falling object after elapsed time .t.
` v_i = sqrt(2gd)`
Instantaneous velocity `v_i` of a falling object that has traveled distance .d.
` v_i = sqrt(2gd)`
(ii) ` u = - 19.6 ms^(-1)`
`u = 9.8 ms^(-2)`
t = 6 sec
height of the building
` s = ut + 1/2 at^2`
` = (-19.6 xx 6) + 1/2 (9.8)(6)^2 = - 117.6 + 176.4`
s = 58.8 m