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The repulsive force between two magnetic...

The repulsive force between two magnetic poles in air is `9 xx 10^(-3)` N. if the two poles are equal in strength and are separated by a distance of 10 cm , calculate the pole strength of each pole .

Text Solution

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The force between two poles are given by ` vec(F) = k (q_(m_(A)) q_(m_(B)))/(r^(2))`
The magnitude of the force is F = k `(q_(m_(A)) q_(m_(B)))/(r^(2))`
Given : F = 9 `xx 10^(-3) N, r = 10` cm = 10 `xx 10^(-2)` m
therefore, `9 xx 10^(-3) = 10^(-7) xx (q_(m)^(2))/((10 xx 10^(-2))^(2)) rArr q_(m) = 30NT^(-1)`
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