A conductor of linear mass density 0.2 g `m^(-1)` suspended by two flexible wire as shown in figure . Suppose the tension in the supporting wires is zero when it is kept inside the magnetic field of 1 T whose direction is into the page. Compute the current inside the conductor and also the direction of the current . Assume g = 10 m`s^(-2)` .

Explanation

Downward force, F = mg
Linear mass density , `(m)/(l) ` = 0.2 `gm^(-1)`
`(m)/(l) = 0.2 xx 10^(-3) kg m^(-1) `
m = `(0.2 xx 10^(-3) xx l ) kg m^(-1) `
F = `(0.2 xx 10^(-3) xx l xx 10)` N
Upward magnetic force acting on the wire
F = BIl
`0.2 xx 10^(-3) xx l xx 10 = 1 xx I xx l `
I = 2 `x 10^(-3)`
I = 2 mA