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An electron is moving at 10^(6) ms^(-1) ...

An electron is moving at `10^(6) ms^(-1)` in a direction parallel to a current of 5A flowing through an infinitely long straight wire , separated by a perpendicular distance of 10 cm in air. Calculate the magnitude of the force experienced by the electron.

Text Solution

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Magnetic field of the straight wire carrying a current of 2A, at a distance of 10cm or 0.1 m from it is
`B = (mu_(0) I)/(2pi r) = (4pi xx 10^(-7)xx 5)/(2i xx 0.1) = 10^(-5)` T
this field acts perpendicular to the direction of the electron . So magnetic force on th electron is
F = qv B sin `90^(@) = 1.6 xx 10^(-19) xx 10^(6) xx 10^(-5) xx 1`
F = `1.6 xx 10^(-18)` N
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