The thickness of a glass slab is 0.25 m. It has a refractive index of 1.5 A ray of light is incident on the surface of the slab at an angle of `60^(@)`. Find the lateral displacement of the light when it emerges from the other side of the mirror.

Explanation

Give: thickness of the lab, (t) =0.25 m, refractive index, (n) =1.5 angle of incidence (i) = `60^(@)`.
Using Snell.s law, `1 xx sin I = n sin r`
`sin r = (sin r)/(n) = (sin 60)/(1.5) = 0.58`
`r = sin^(-1)(0.58) = 35,256(@)`
Latereal displacement is, `L=t((sin(i-r))/(cos(r)))`
`L=(0.25)xx((sin(60-35.25))/(cos(35.25)))=0.1281m`
The lateral displacement is, `L = 12.81 cm`