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The angle of minimum deviation for a pr...

The angle of minimum deviation for a prism is `37^(@)`.If the angle of prism is `60^(@)` , find the refractive index of the material of the prism.

Text Solution

Verified by Experts

Give: A = `60^(@) , , D = 37^(@!)`
Equation for refractive index is, `n=(sin((A+D)/(2)))/(sin((A)/(2)))`
Substituting the values `n=(sin((60^(@)+37^(@))/(2)))/(sin((60^(@))/(2)))=(sin(48.5))/(sin(30^(@)))=(0.75)/(0.5)=1.5`
The refractive index of the flint glass is, `omega = 0.0306`
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