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A monochromatic light of wavelenght 500...

A monochromatic light of wavelenght 5000Å passes through a single slit producing diffraction pattern for the central maximum as shown in the figure. Determine that width of the slit.

Text Solution

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`lambda=5000Å=5000xx10^(-10)m,sin30^(@)=0.5,n=1,a=?`
Equation for diffraction minimum is, ` a sin theta = n lambda`
The central maximum is spread up to the first minimum. Hence, n = 1
Rewriting, `a = (lambda)/(sin theta)`
Substituting, `a=(5000xx10^(-10))/(0.5)`
`a=1xx10^(-6)m=0.001xx10^(-3)m=0.001mm`
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