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Calculate the distance for which ray op...

Calculate the distance for which ray optics is good aproximation for an aperture of 5 mm and wavelenght 500 nm.

Text Solution

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`a = 5 mm = 5 xx 10^(-3) m ,`
`lambda = 500 nm = 500 xx 10^(-9) m, z = ?`
Equation for Fresnel.s distance, `z = (a^(2))/(2 lambda)`
Substituting, `z=((5xx10^(-3))^(2))/(2xx500xx10^(-9))=(25xx10^(-6))/(1xx10^(-6))=25m`
z = 25 m
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