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First diffraction minimum due to a singl...

First diffraction minimum due to a single slit of width `1.0xx10^(-5)` cm is at `30^@`. Then wavelength of light used is,

A

400 Å

B

500 Å

C

600 Å

D

700 Å

Text Solution

Verified by Experts

For diffraction minima, `d sin theta = n lambda`
`lambda=(dsintheta)/(n)=(1xx10^(-5)xx10^(-2)xxsin30^(@))/(1)=0.5xx10^(-7)`
`lambda = 500 Å`
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