How does refractive index `(mu)` of a material vary with respect to wavelenght `(lambda)`. (A and B are constants).

Options

A. `mu = A + (B)/(lambda^(2))`
B. `mu = A + Blambda^(2))`
C. `mu = A + (B)/(lambda)`
D. `mu = A = B lambda`

Answer

A, B, D

Explanation

According to cauchy.s relation, `mu = A + (B)/(lambda^(2))`