A prism of a refracting angle `60^(@)` is made with a material of refractive index `mu`. For a certain wavelength of light, the angle of minimum deviation is `30^(@)`. For this wavelength, the value of `mu` of material is

Options

A. 1.82
B. 1.414
C. 1.503
D. 1.231

Answer

A, D

Explanation

`mu=(sin((60^(@)+30^(@))/(2)))/(sin30^(@))=(sin45^(@))/(sin30^(@))=(1)/(sqrt(2))xx(2)/(1)=sqrt(2) = 1.414`