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Assuming that energy released by the fis...

Assuming that energy released by the fission of a single `""_(92)^(235)U` nucleus is 200MeV, calculate the number of fissions per second required to produce 1 kilowatt power.

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Let the number of fissins per second be n.
Then, Energy released per second = `n xx 200 MeV`
`= n xx 200 xx1.6 xx 10^(-13)`J
Energy required per second = Power `xx` Time
`= 1kW xx 1s = 1000`J
Energy released = Energy required
`n xx 200 xx1.6 xx 10^(-13) = 1000`
`n = 3.125 xx 10^(13)`.
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