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Find the current through the Zener diode...

Find the current through the Zener diode When the load resitence is 2 K `Omega`.Use diode approximation.

Text Solution

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Voltage across AB is `V_Z=9V`
Voltage drop across R=15-9=6V
Therefore current through the resistor R.
`1=(6)/(6xx10^(3))`=6mA.
Voltahe across the load resistor=`V_(AB)=9V`
Current through load resistor,`I_L=(V_AB)/(R_L)=(9)/(2xx10^3)=4.5mA`
The current through the Zener diode,`I_Z=I-I_L=6mA-4.5mA=1.5mA`
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