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The current gain of a common emitter tra...

The current gain of a common emitter transiter circuit shown in figure is
. Draw the dc load line and mark the Q point on it .

Text Solution

Verified by Experts

`Beta=120`
Base current`I_B=(25V)/(1MOmega)=(25)/(1xx10^6)=25muA`
`beta=(I_C)/(I_B),I_C=betaI_B`
`I_C=120xx25muA`
`I_C=3mA`
`V_CE=V_CC-I_CR_C`
`V_CE=25-3mAxx5k`
`V_CE=10V`
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