Home
Class 12
PHYSICS
In common - emitter amplifier the ratio ...

In common - emitter amplifier the ratio `(I_C)/(I_E)` 0.98. The current gain will be

A

4.9

B

7.8

C

49

D

78

Text Solution

Verified by Experts

The correct Answer is:
c

Here `alpha=(I_C)/(I_E)=0.98`
`beta=(alpha)/(1-alpha)=(0.98)/(1-0.98)=(0.98)/(0.02)=49`
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTOR ELECTRONICS

    FULL MARKS|Exercise Additional Question (Short Answer Questions)|22 Videos
  • SEMICONDUCTOR ELECTRONICS

    FULL MARKS|Exercise Additional Question (Long Answer Questions.)|3 Videos
  • SEMICONDUCTOR ELECTRONICS

    FULL MARKS|Exercise Textual Evaluation Solved (Numerical Problems)|5 Videos
  • SAMPLE PAPER-8

    FULL MARKS|Exercise PART-IV|10 Videos

Similar Questions

Explore conceptually related problems

Consider an n-p-n transistor amplifier in common - emitter configuration. The current gain of the transistor is 100. If the collector current changes by 1 mA, what will be the change in emitter current?

What is the phase relationship between the AC input and output voltages in a common emitter amplifier ? What is the reason for the phase reversal ?

In a common emitter transistor amplifier the audio signal voltage across the collector is 3K Omega .If current gain is 100 and the base resistance is 2KOmega , the voltage and power gain of the amplifies is :

For a common emitter amplifier , current gain is 70 . If the emitter is 8.8 mA , calculate the collector and base current . Also calculate current gain , when transistor is worked on common base amplifier .

The current gain for a transistor working as common base amplifier is 0.96. If the emitter current is 7.2 mA, then the base current is

A common - emitter amplifier has a voltage gain of 100 an, input impendence of 100Omega and an output impendence of 200Omega . The product of voltage gain and current gain is ………