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In an P.N.P transistor circuit, the coll...

In an P.N.P transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector.

Text Solution

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Here, `I_E=10mA`
As 90% of the holes reach the collector, so the collector, so the collector currents.
`I_C=90%of I_E`
`I_C=(90)/(100)I_E`
`I_E=(100)/(90)I_C=(100)/(90)xx10`
`I_E~=11mA`
Base current, `I_B=I_E-I_C=11-10`
`I_B=1 mA`
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