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When a point charge of 6 mu C is moved b...

When a point charge of `6 mu C` is moved between two points in an electric field, the work done is `1.8 xx 10^(-5) J`. The potential difference between the two points is :

A

1.08 V

B

`1.08 muV`

C

3V

D

30V

Text Solution

Verified by Experts

Potential difference (V)=`"workdone (W)"/"change (q)"`
`=(1.8xx10^(-5))/(6xx10^(-6))=18/6`
V=3V
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