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In a transistor connected in the common...

In a transistor connected in the common base configuartion, `alpha=0.95,I_E=1mA`.Calculate the value of `I_C` and `I_B`.

Text Solution

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`alpha=I_(C)/I_(E)`
`I_(C)=alphaI_(E)=0.95xx 1=0.95mA`
`I_(E)=I_(B)+I_(C)`
`I_(B)=I_(C)-I_(E)=1-0.95 =0.05mA`
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