Home
Class 12
PHYSICS
The horizontal component of earth's magn...

The horizontal component of earth's magnetic field at a place is `3.6 xx 10^(-5)` T. if the angle of dip at this place is `60^(@)`, the vertical components of earth's field at this place is

A

`1.2 xx 10^(-5)T`

B

`2.4 xx10^(-5)T`

C

`4 xx 10^(-5)T`

D

`6.2 xx 10^(-5)T`

Text Solution

Verified by Experts

`B_v=B_H tan delta =3.6 xx10^(-5) xx tan 60^@`
`B_v=6.2 xx10^(-5)T`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER -4 (SOLVED)

    FULL MARKS|Exercise PART-II|9 Videos

  • SAMPLE PAPER -4 (SOLVED)

    FULL MARKS|Exercise PART-III|9 Videos

  • SAMPLE PAPER -14 (UNSOLVED)

    FULL MARKS|Exercise PART-IV|9 Videos

  • SAMPLE PAPER 3 (SOLVED)

    FULL MARKS|Exercise PART- IV|10 Videos

Similar Questions

Explore conceptually related problems

What is meant by horizontal component of Earth's magnetic field.

a. Where on the earth's surface is the value of vertical component of the earth's magnetic field zero ? b. The horizontal component of the earth's magnetic field at a given place is 0.4xx10^(-4) Wb//m^2 and angle of dip is 30^@ Calculate the value of (i) vertical component (ii) the total intensity of the earth's magnetic field.

Angle of dip at a place, wher horizontal and verical componet of earth's fiedl are qual is

The angle of dip at a place where horizontal and vertical components of earth's magnetic field a equal is

At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^(@) . What is the value of horizontal component of the earth's magnetic field at equator ?

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

Write the value of vertical component of Earth's magnetic field.

The horizontal component of the earth's magnetic field at a place is 3.0 X 10^(-4) T and the dip is 53^@ . A metal rod of length 25cm is placed in the north - south direction and is moved at a constant speed of 10cm s^(-1) towards east. Calculate the emf induced in the rod.

The horizontal component of the earth's magnetic field at a certain place is 3.0 xx 10^(-5) T and the direction of the field is form the geographic south to the georgraphic north . A very long straihgt conductor is carrying a steady current of 1 . What is the force par unit length on it when it is placed on horizontal table and the direction of the current is (a) east to west , (b) south to north ?

The vertical component of Earth's magnetic field at a place is equal to the horizontal component. What is the value of angle of dip at this place ?