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A coil of a tangent galvanometer of diam...

A coil of a tangent galvanometer of diametre 0.24 m has 100 turns. If the horizontal component of Earth's magnetic field is `25 xx 10^(-6)` T then, calculate the current which gives a deflection of `60^(@)` .

Text Solution

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The diameter of the coil is 0.24 m. Therefore, radius of the coil is 0.12 m. Number of turns is 100 turns, Earth.s magnetic field is `25xx10^(-6)T`
Deflection is `theta=60^(@)impliestan 60^(@)=sqrt3=1.732`
`1=underline(2RB)tan theta=(2xx0.12xx25xx10^(-16))/(4xx10^(-7)xx3.14xx100)xx1.732=0.82xx10^(-1)A`
`1=0.082A`
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