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First diffraction minimum due to a singl...

First diffraction minimum due to a single slit of width `1.0xx10^(-5)` cm is at `30^@`. Then wavelength of light used is,

A

400 A

B

500 Å

C

600 A

D

700 Å

Text Solution

Verified by Experts

The correct Answer is:
b
For diffraction minima, d sin `theta = nlambda`
`lambda=(dsintheta)/(n)=(1xx10^(-5)xxsin30^(@))/(1)=0.5xx10^(-7)`
`lambda=500A`
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