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The current in an inductive circuit is g...

The current in an inductive circuit is given by `0.3 sin(200t - 40^(@))` A. Write the equation for the voltage across it if the inductance is 40 mH.

Text Solution

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`L = 40 xx10^(-3H), i = 0.1 sin (200t-40^(@)), X_(L) = omegaL= 200 x× 40 x× 10^(-3) = 8Omega, V_(m)=I_(m)X_(L)= 0.3 xx 8 = 2.4 V`
In an inductive circuit, the voltage leads the current by `90^(@)` Therefore,
`upsilon = V_(m) sin (omega +90^(@))`
`upsilon = 2.4 sin (200t - 40^(@)+90^(@))`
`upsilon = 2.4 sin (200t +50^(@))vol t`
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