Home
Class 12
PHYSICS
An electron and an alpha particle have s...

An electron and an alpha particle have same kinetic energy. How are the de Broglie wavelengths associated with them related ?

Text Solution

Verified by Experts

Kinetic energy of the particle `K=1/2mv^(2)=(P^(2))/(2m)=(h^(2))/(2mlambda^(2))[lambda=h/P]`
i.e `lambda =h/(sqrt(2mK)),lambda prop1/(sqrtm)`
`(lambda_e)/(lambda_prop)=sqrt((m_prop)/(m_e))`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER-8

    FULL MARKS|Exercise PART-IV|10 Videos

  • SAMPLE PAPER-8

    FULL MARKS|Exercise PART-II|9 Videos

  • SAMPLE PAPER-6

    FULL MARKS|Exercise PART - III|18 Videos

  • SEMICONDUCTOR ELECTRONICS

    FULL MARKS|Exercise Additional Question(Numerical problems.)|6 Videos

Similar Questions

Explore conceptually related problems

An electron of mass m and photon have same energy E. The ratio of de-Broglie wavelength associated with them is:

A proton and an electron have same kinetic energy. Which one has greater de Broglie wavelength. Justify.

An electron and a proton are moving in the same direction and possess same kinetic energies. Find the ratio of de Broglie wavelength associated with these particles.

An electron and a proton have same speed. How are their wavelength related?