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A coil of 200 turns carries a current of...

A coil of 200 turns carries a current of o.4 A. If the magnetic flux of 4 m Wb is linked with the coil, find the inductance of the coil.

Text Solution

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Number of turns, N= 200, Current, I = 0।4 A
Magnetic flux linked with coil, `phi = 4 mWb = 4 x 10^(-3) `Wb
Induction of the coil,`L=phi/I=200xx4xx10^(-3)/(0।4)=800xx10^(-3)/(0।4)=2H`
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