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If the nuclear radius of ""^(27)Al is 3....

If the nuclear radius of `""^(27)Al` is 3.6 fermi, the approximate nuclear radius of `""^(64)Cu` is

A

2.4

B

1.2

C

4.8

D

3.6

Text Solution

Verified by Experts

The correct Answer is:
C
`R_(Al)/R_(Cu)=(27)^(1//3)/(64)^(1//3)=3/4`
`R_(Cu)=4/3R_(Al)=4/3xx3.6` fermi
`R_(Cu)`=4.8 fermi
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