The nucleus is approximately spherical in shape. Then the surface area of nucleus haviing mass number A varies as.

Options

A. `A^(2//3)`
B. `A^(4//3)`
C. `A^(1//3)`
D. `A^(5//3)`

Answer

A

Explanation

`A^(2//3)`
Volume of nucleus is proportional to mass number
`(4)/(3) pi R^(3) prop A , R = R_(0) A^(1//3)`
So, ` 4pi R^(2) = R_(0) A^(2//3) rArr 4 pi R^(2) prop A^(2//3)`
Surface area is proportional to `("mass number")^(2//3)`