The equation for an alternating current is given by `i=77` sin 314t. Find the peak value .

Explanation

i=77 sin 314, t = t =2 ms = `2xx 10^(-3) s `
The general eqution of an alternating current is ` I = I_(s)` sin `omegat` . On comparison .
(i) Peak value, ` I_(m) = 77A`
(ii) Frequency , `f = (omega)/(2pi) = (314)/(2 xx 3.14) = 50Hz`
(iii) Time period, ` T = (1)/(f) = (1)/(50) = 0.02s`
(iv) At `" "t = 2 ms`
Instataneous value ` i = 77 sin (314 xx 2 xx 10^(-3)) = 42.24 A`