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Resistance of a material at 10^(@)C and ...

Resistance of a material at `10^(@)C` and `40^(@)C` are `45Omega` and `85Omega` respectively. Find its temperature co-efficient of resistance

Text Solution

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`T_(0) = 10^(@)C,= 40^(@)C, R_(0) = 45 Omega, R = 85 Omega`
`alpha = (1)/(R_(0))(Delta R)/(Delta T) rArr alpha = (1)/(45) ((85 div 85)/(40-10))= 1/45 ((40)/(30))`
`alpha = 0.0296 per^(@)C`
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